" If "m" and "n" are positive integers and "f(x)=int_(1)^(x)(t-a)^(2n)(t-b)^(2m+1)dt,a!=b," then "

If f(x)=int_(1)^(x)(ln t)/(1+t)dt, then

If m, n in R , then the value of I(m,n)=int_(0)^(1) t^(m)(1+t)^(n)dt is -

If F(x)=int_(1)^(x)(ln t)/(1+t+t^(2))dt then F(x)=-F((1)/(x))

Let T_(r) be the rth term of an AP, for r=1,2,… If for some positive integers m and n, we have T_(m)=(1)/(n) and T_(n)=(1)/(m)," the "T_(m+n) equals

Let f(x)=int_(1)^(x)t(t^(2)-3t+2)dt,1lexle4 . Then the range of f (x) is

A periodic function with period 1 is integrable over any finite interval.Also,for two real numbers a,b and two unequal non-zero positive integers m and nint_(a)^(a+n)f(x)dx=int_(b)^(b+m)f(x) calculate the value of int_(m)^(n)f(x)dx

Let f(x)=int_(0)^(x)e^(t)(t-1)(t-2)dt. Then, f decreases in the interval