If `f(x)=(tan(pi/4+(log)_e x))^((log)_x e)` is to be made continuous at `x=1,` then what is the value of `f(1)?`

For the function f(x) = (log_(e )(1+x)-log_(e )(1-x))/(x) to be continuous at x = 0, the value of f(0) should be

For the function f(x)=(log_(e)(1+x)+log_(e)(1-x))/(x) to be continuous at x = 0, the value of f(0) is

If f(x)=(log)_(e)((log)_(e)x), then write the value of f'(e)

If f(x) = {((log_(e )x)/(x-1), ",", x != 1),(k, ",", x = 1):} is continuous at x = 1, then the value of k is

let f(x)=(ln cos x)/((1+x^(2))^((1)/(4))-1) if x>0 and f(x)=(e^(sin4x)-1)/(ln(1+tan2x)) if x<0 Is it possible to difine f(0) to make the function continuous at x=0. If yes what is.the value of f(0), if not then indicate the nature of discontinuity.

The function f(x)=((3^(x)-1)^(2))/(sin x*ln(1+x)),x!=0, is continuous at x=0, Then the value of f(0) is

If f(x)=log_(e)(log_(e)x)/log_(e)x then f'(x) at x = e is

If the f(x) =(log(1+ax)-log(1-bx))/x , xne0 is continuous at x = 0 then, f(0) = .....

Let f(x)=(e^(tan x)-e^(x)+ln(sec x+tan x)-x)/(tan x-x) be a continuous function at x=0. The value f(0) equals