" If "x=(6y+4)(3y^(2)+4y+3)" then "int xdy" will be: "

If x=(6y+4)(3y^(2)+4y+3) then intxdy will be :

If x=(6y+4)(3y^(2)+4y+3) then intxdy will be :

xdy = (x ^ (3) y ^ (6) -y) dx

If (3x -4y) : (2x -3y) = (5x -6y) : (4x -5y) , find : x : y .

If r_(1), r_(2) " and " r_(3) are the radii of the circle x^(2) + y^(2) - 4x + 6y = 5 , x^(2) + y^(2) + 6x - 4y = 3 " and " x^(2) + y^(2) - 2x + 4y = 8

ydx-xdy = x ^ (8) y ^ (5) (3ydx + 4xdy)

IF x cos ( y //x ) ( ydx + xdy)=y sin ( y // x) ( xdy - ydx ) y (1) = 2 pi then the value of 4 ( y (4) )/(pi ) cos (( y (4))/(4)) is :

IF x cos ( y //x ) ( ydx + xdy)=y sin ( y // x) ( xdy - ydx ) y (1) = 2 pi then the value of 4 ( y (4) )/(pi ) cos (( y (4))/(4)) is :