Find the number of points of discontinuity for `f(x)=[6sinx], 0<=x<=pi`

Write the number of points of discontinuity of f(x)=[x] in [3,7] .

Let f(x)=[3+2cos x],x in(-(pi)/(2),(pi)/(2)) where [.] is the GIF .Then the number of points of discontinuity of f(x) is

Given f(x)=|x+1| if x =3 then number of points of discontinuity of f(x) is

Let f (x)= signum (x) and g (x) =x (x ^(2) -10x+21), then the number of points of discontinuity of f [g (x)] is

Let g(x)=f(f(x)) where f(x)={1+x;0<=x<=2} and f(x)={3-x;2

If f(x) = sgn (x) and g (x) = (1-x^2) ,then the number of points of discontinuity of function f (g (x)) is -

[" If "],[" f(x) "=sgn(3x cos^(-1)(x)-6cos^(-1)(x)-pi x+2 pi)],[" ,then the number of points "],[" of discontinuity of "f(x)" is/are "],[" [Note: sgn k denotes signum "],[" function of k.] "]