Find the number of integers lying in the interval (0,4) where the function `f(x)=(lim)_(nvecoo)(cos(pix)/2)^(2n)` is discontinuous

The number of integers lying in the domain of the function f(x)=sqrt(log_(0.5)((5-2x)/(x))) is-

The points where f(x)=lim_(x rarr oo)(sin(pi(x)/(2)))^(2)n is discontinuous are:

Let f(x)=lim_(n to oo) sinx/(1+(2 sin x)^(2n)) then f is discontinuous at

In the interval (0, (pi)/(2)) the function f (x) = cos ^(2) x is :

The function f(x)=lim_(nrarroo)((x-2)^(2n)-1)/((x-2)^(2n)+1) (AA n in N) is discontinuous at

Let f(x)=[x^3 - 3], where [.] is the greatest integer function, then the number of points in the interval (1,2) where function is discontinuous is (A) 4 (B) 5 (C) 6 (D) 7

Discuss the continuity of f(x) in [0, 2], where f(x)=(lim)_(n->oo)(sin(pix)/2)^(2n)dot

Draw the graph of the function y=f(x)=lim_(ntooo) cos^(2n)x and find its period.

Find the intervals in which the function f given by f(x)=(4sin x-2x-x cos x)/(2+cos x),0<=x<=2 pi

Let f(x)=[x^(2)]sin pi x , x in R , the number of points in the interval (0,3] at which the function is discontinuous is _