`(tanalphasec^2alpha+cotalphacosec^2alpha)-(tanalpha+cotalpha)=2cosec2alpha[sec^2alpha+cosec^2alpha-3]`

Prove that (sinalpha+cosalpha)(tanalpha+cotalpha)=secalpha+"cosec"alpha

tan2alpha-tanalpha(1+sec2alpha)=

If tan alpha=2 , then the value of (cosec^2 alpha-sec^2 alpha)/(cosec^2 alpha+sec^2 alpha) is यदि tan alpha=2 है, तो (cosec^2 alpha-sec^2 alpha)/(cosec^2 alpha+sec^2 alpha) का मान ज्ञात करें।

1/(tan3alpha-tanalpha)-1/(cot3alpha-cotalpha)=cot2alpha

The value of (cosec alpha-sin alpha)(sec alpha-cos alpha)(tan alpha+cot alpha) (cosec alpha-sin alpha)(sec alpha-cos alpha)(tan alpha+cot alpha) का मान क्या है?

(sin alpha)/(1+cos alpha)+(1+cos alpha)/(sin alpha)=2cosec alpha

(cotalpha+"cosec"alpha-1)/(cotalpha-"cosec"alpha+1)=(1+cosalpha)/(sinalpha)

If cot^3alpha+cot^2alpha+cotalpha=1 then (a) cos2alpha.tanalpha=-1 (b)cos2alpha.tanalpha=1 (c) cos2alpha-tan2alpha=1 (d)cos2alpha-tan2alpha=-1

If cot^3alpha+cot^2alpha+cotalpha=1 then (a) cos2alpha.tanalpha=-1 (b) cos2alpha.tanalpha=1 (c) cos2alpha-tan2alpha=1 (d) cos2alpha-tan2alpha=-1

If cot^3alpha+cot^2alpha+cotalpha=1 then (a) cos2alpha.tanalpha=-1 (b) cos2alpha.tanalpha=1 (c) cos2alpha-tan2alpha=1 (d) cos2alpha-tan2alpha=-1