Suppose that 90% of people are right-handed. What is the probability that at most 6 of a random sample of 10 people are right-handed?

Explanation

To solve the problem, we need to find the probability that at most 6 out of 10 people are right-handed, given that 90% of people are right-handed. This situation can be modeled using the binomial probability formula.

### Step-by-Step Solution:

1. **Identify Parameters**:
- Let \( n = 10 \) (the number of trials, or people sampled).
- Let \( p = 0.9 \) (the probability of success, i.e., a person being right-handed).
- Let \( q = 1 - p = 0.1 \) (the probability of failure, i.e., a person being left-handed).
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