`8sin theta costhetacos 2theta cos 4theta = sinx quad => x=`

8 sin theta cos theta cos 2 theta cos 4 theta =

8sin theta cos theta cos2 theta cos4 theta=sin x the x=

If 8sin theta cos theta cos2theta cos4theta=sinx then x=

8sin theta cos theta*cos2 theta cos4 theta=sin x rArr x=

8 sin theta * cos theta * cos 2 theta * cos 4 theta = A) sin 4 theta B) sin 8 theta C) sin 16 theta D) cos 8 theta

Prove the following: 2^(3)sin theta cos theta cos2 theta cos4 theta=sin8 theta

sin^2theta+cos^4theta=cos^2theta+sin^4theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

If 8 sin theta=4+cos theta then sin theta=