A uniform disc is rolling on a horizontal surface. At a certain instant `B` is the point of contact and `A` is at height `2 R` from ground, where `R` is radius of disc -
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A uniform circular disc of radius R is rolling on a horizontal surface. Determine the tangential velocity : at the upper most point

A uniform circular disc of radius R is rolling on a horizontal surface. Determine the tangential velocity : the centre of mass

A uniform circular disc of radius R is rolling on a horizontal surface. Determine the tangential velocity (i) at the upper most point (ii) at the centre of mass and (iii) at the point of contact.

A uniform disc of radius R is in pure rolling on a fixed horizontal surface with constant speed v_0 as shown in the figure. For what value of theta , speed of point P will be v_0/2√(5+2√3) ? (OP= R/2 and O is the centre of disc)

A disc shaped body (having a hole shown in the figure) of mass m=10kg and radius R=10/9m is performing pure rolling motion on a rough horizontal surface. In the figure point O is geometrical center of the disc and at this instant the centre of mass C of the disc is at same horizontal level with O . The radius of gyration of the disc about an axis pasing through C and perpendicular to the plane of the disc is R/2 and at the insant shown the angular velocity of the disc is omega=sqrt(g/R) rad/sec in clockwise sence. g is gravitation acceleration =10m//s^(2) . Find angular acceleation alpha ( in rad//s^(2) ) of the disc at this instant.

A disc shaped body (having a hole shown in the figure) of mass m=10kg and radius R=10/9m is performing pure rolling motion on a rough horizontal surface. In the figure point O is geometrical center of the disc and at this instant the centre of mass C of the disc is at same horizontal level with O . The radius of gyration of the disc about an axis pasing through C and perpendicular to the plane of the disc is R/2 and at the insant shown the angular velocity of the disc is omega=sqrt(g/R) rad/sec in clockwise sence. g is gravitation acceleration =10m//s^(2) . Find angular acceleation alpha ( in rad//s^(2) ) of the disc at this instant.

A disc of radius 0.2 m is rolling with slipping on a flat horizontal surface, as shown in Fig. The instantaneous centre of rotation is (the lowest contact point is O and centre of disc is C )

A disc of radius 0.2 m is rolling with slipping on a flat horizontal surface, as shown in Fig. The instantaneous centre of rotation is (the lowest contact point is O and centre of disc is C )