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A bag consists of 10 balls each marked ...

A bag consists of 10 balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag, what is the probability that none is marked with the digit 0?

Text Solution

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`0,1,2,3,4,5,6,7,8,9`
`I-> 9/10`
`II -> 9/10`
`III -> 9/10`
`P =(9/10)(9/10)(9/10)(9/10) = (9/10)^4`
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