If `(3iz_2)/(5z_1)` is purely real, then `5(|3z_1+7z_2|)/(|3z_1-7z_2|)` is

If (5z_2)/(7z_1) is purely imaginary , then |(2z_1+3z_2)/(2z_1-3z_2)|=

Let z_(1), z_(2) be two complex numbers such that z_(1) ne 0 and z_(2)//z_(1) is purely real, then |(2i z_(1) + 5 z_(2))/(2iz_(1)-5z_(2))| is equal to

If (5z_2)/(7z_1) is purely imaginary, then |(2z_1+3z_2)/(2z_1-3z_2)|= (A) 5/7 (B) 7/9 (C) 25/49 (D) 1

if (5z_2)/(7z_1) is purely imaginary number then |(2z_1+3z_2)/(2z_1-3z_2) | is equal to

If (2z_1)/(3z_2) is purely imaginary then |(z_(1)-z_(2))/(z_(1)+z_(2))|

If (5z_(2))/(7z_(1)) is purely imaginary,then |(2z_(1)+3z_(2))/(2z_(1)-3z_(2))|=(A)(5)/(7)(B)(7)/(9)(C)(25)/(49)(D)1

If (3 z_(1))/(5 z_(2)) is purely imaginary, then |(2z_(1)-z_(2))/(2z_(1) + z_(2))| is equal to _________

Column I, Column II (Locus) parallelogram, p. z_1-z_4=z_2-z_3 rectangle, q. |z_1-z_(3|)=|z_2-z_(4|) rhombus, r. (z_1-z_2)/(z_3-z_4) is purely real square, s. (z_1-z_3)/(z_2-z_4) is purely imaginary , t. (z_1-z_2)/(z_3-z_2) is purely imaginary