The equation `[1 x y][(1,3,1),(0,2,-1),(0,2,-1)] [(1),(x),(y)]=[0]` has

The equation [1 x y][(1,3,1),(0,2,-1),(0,0,1)] [(1),(x),(y)]=[0] has i)for y=0 (p) rational roots ii) for y=-1 (q) irrational roots (r) integral roots

The solutiion of (x,y,z) the equation [(-1,0,1),(-1,1,0),(0,-1,1)][(x),(y),(z)]=[(1),(1),(2)] is (x,y,z)

The solutiion of (x,y,z) the equation [(-1,0,1),(-1,1,0),(0,-1,1)][(x),(y),(z)]=[(1),(1),(2)] is (x,y,z)

The roots of the equation det [(1-x, 2, 3),(0,2-x,0),(0,2,3-x)]=0 are (A) 1 and 2 (B) 1 and 3 (C) 2 and 3 (D) 1,2, and 3

The roots of the equation det [(1-x, 2, 3),(0,2-x,0),(0,2,3-x)]=0 are (A) 1 and 2 (B) 1 and 3 (C) 2 and 3 (D) 1,2, and 3

Use the product [(1,-1,2),(0,2,-3),(3,-2,4)][(-2,-0,1),(9,2,-3),(6,1,-2)] to solve the system of equations x - y + 2z = 1 2y - 3z = 1 3x - 2y + 4z = 2

Find the value of (x+y) from the following equation: 2{:[(1,3),(0,x)] + [(y,0),(1,2)] = [(5,6),(1,8)] .