The length of the altitudes from the vertices A,B,C of a triangle ABC to opposite sides are `24,18,(72)/(5)` respectively. If `Delta` is the area of the triangle ABC then `root(3)(Delta)` is equal to

The altitudes from A B , C to opposite sides of triangle ABC are 24,18,(72)/(5) respectively. If delta is area of /_\ ABC . Then root(3)(delta)=

Let the lengths of the altitudes drawn from the vertices of Delta ABC to the opposite sides are 2, 2 and 3. If the area of Delta ABC " is " Delta , then find the area of triangle

The altitudes from the vertices A,B,C of an acute angled triangle ABC to the opposite sides meet the circumcircle at D,E,F respectively . Then (EF)/(BC) =

If the altitudes from two vertices of a triangle to the opposite sides are equal,prove that the triangle is isosceles.

If the altitudes from two vertices of a triangle to the opposite sides are equal,prove that the triangle is isosceles.

The length of altitude through the vertex A of triangle ABC,The position vectors of whose vertices are bar(a),bar(b),bar(c)

The lengths of the tangents drawn from the vertices A,B,C to the incircle of Delta ABC are 5,3,2 respectively.If the lengths of the parts of tangents within the triangle which are drawn parallel tothe sides BC,CA,AB of the triangle to the incirclebe alpha,beta,gamma respectively then (10)/(31)(alpha+beta+gamma) equals

If in a Delta ABC, the altitudes from the vertices A,B,C on opposite sides are in H.P.then sin Asin B, sin C are in

The vertices of ABC are (-2,1),(5,4) and (2,-3) respectively.Find the area of the triangle and the length of the altitude through A.