\(K_{4}[Fe(CN)_{6}]\rightarrow Fe^{+3}+CO_{2}+NO_{2}\) In the given chemical equation Equivalent weight of \(K_{4}[Fe(CN)_{6}]\) is \(\frac{M}{x}\). M is molecular weight of \(K_{4}[Fe(CN)_{6}]\). What is the value of \(\frac{x}{11}\)