`6 g` of `H_(2)` reacts with `14gN_(2)` to form `NH_(3)` till the reaction completely consumes the limiting reagent.The amount of other reactant (in `g` ) left are .......

B_(2)H_(6) reacts with NH_(3) to form

80 g of H_(2) is reacted with 80 g of O_(2) to form water. Find out the mass of water obtained. Which substance is the limiting reagent ?

3.0 g of H_(2) react with 29.0 g O_(2) to yield H_(2)O (i) What is the limiting reactant ? (ii) Calculate the maximum amount of water that can be formed (iii) Calculate the amount of one of the reactants which remains unreacted.

When 3.0 g of H_(2) react with 29.Og of O_(2) to form water, O_(2) is the limiting reactant. statement is true or false