The area bounded by `y=sin x` with `y` -axis for `x` in`[-(pi)/(2),(pi)/(2)]` is

Find the area bounded by y = sin x and axis of x in (0 , pi)

The area bounded by the curve y=cosx and y=sin 2x, AA x in [(pi)/(6), (pi)/(2)] is equal to

The area bounded by y = |sin x|, X-axis and the line |x|=pi is

The area bounded by y=x|sin x| and x -axis between x=0,x=2 pi is

The area bounded by y=sin^(-1)x , y-axis and |y|=(pi)/(2) is

The area bounded by y=tan x,y=cot x,x axis in 0<=x<=(pi)/(2) is

If area bounded by f(x)=sin(x^(2)) with x axis,from x=0 to x=sqrt((pi)/(2)) is A,then

The area bounded by the curve y=sin x between x=(pi)/(2) and x=(3 pi)/(2)

Find the area bounded by y=sin^(-1)(sin x) and x=axis for x in[0,100 pi]

If A_(1) is the area bounded by the curve y = cos x and A_(2) is the area bounded by y = cos 2 x along with x - axis from x = 0 and x = (pi)/(0) , then