" If "g(x)" is the inverse of "f(x)=x+sin x" then area bounded by "y=g(x)" between "y=0,y=2 pi" and "y-axis

The area bounded by y=x|sin x| and x -axis between x=0,x=2 pi is

Find the area bounded by the curve y=sin x between x=0 and x=2 pi

Find the area bounded by the curve y=sin x between x=0 and x=2 pi.

The area bounded by the curves y=In x,y=|ln x| and the y-axis is

Area bounded by the curve y=sin x between .x=0 and x=2 pi is

The area bounded by y=x+1 and y=cos x and the x - axis, is

Let y=g(x) be the image of f(x)=x+sin x about the line x+y=0 .If the area bounded by y=g(x) ,x-axis, x=0 and x=2 pi is "A" ,then (A)/(pi^(2)) is .......

For 0<=x<=pi, the area bounded by y=x and y=x+sin x, is

The area bounded by the curve y = sin2x, axis and y=1, is