Morning breakfast gives 5000 cal to a 60 kg person.The efficiency of person is 30%. The height upto which the person can climb up by using energy obtained from breakfast is

Morning breakfast gives "5000" cal to a 60kg person.The efficiency of person is 30%.The efficiency of person is 30% .The height upto which the person can climb up by using energy obtained from breakfast is

A bread gives a boy of mass 40 kg an energy of 21 kJ. If the efficiency is 28%, then the height that can be climbed by him using this energy, is :

A worker eats a dish of icecream which funishes 200 kcal of heat. If the efficiency of the body is 25%, then calculate the height to which the worker can carry a weight of 56 kg using the energy of icecream. Worker's own weight is 70 kg. Given J = 4.2 J cal^(-1) .

A man of 60kg gains 1000 cal of heat by eating 5 mangoes. His efficiency is 56%. To what height he can jump by using this energy?

A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficiency is 29% . To what height he can jump by using this energy?

The mass of a metallic beam of uniform thickness and of length 6m is 60kg . The beam is horizontally and symmetrically lies on two vertical pillars which are separated by a distance 3m . A person of mass 75kg is walking on this beam. The closest distance to which the person can approach one end of the beam so that the beam does not tilt down is (neglect thickness of pillars)

The weight of a person is 60 kg . If he gets 10 calories of heat through food and the efficiency of his body is 28% , then upto what height he can climb? Take g = 10m s^(-2)

The weight of a person is 60 kg . If he gets 105 calories heat through food and the efficiency of his body is 28%, then upto how much height he can climb (approximately)

A 60 kg person climbs stairs of total height 20m in 2min. Calculate the power deliverd.