The equation of the locus of the points equidistant from the point `A(-2,3)` and `B(6,-5) is

The equation of the locus of the points equidistant from the points A(-2,3) & B(6,-5) is

Locus of the points equidistant from the point (-1, -1) and (4, 2) is

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is

Find the equation of the locus of the point P equidistant from the points (2,3),(1,4)

The equation of the locus of points which are equidistant from the points (2,-3) and (3,-2) is (A) x+y=0 (B) x+y=7 (C) 4x+4y=38 (D) x+y=1

Find the equation to the locus of a point equidistant from the points A(1,3) and B(-2,1) .

Find the equation of the locus of the point P equidistant from the points (-3,2),(0,4)

If the equation of the locus of a point equidistant from the points (a_1,b_1) and (a_2,b_2) is (a_1-a_2)x+(b_2+b_2)y+c=0 , then the value of C is

Find the equation of the locus of the point "P" equidistant from the points (-3,2),(0,4)

Find the locus of the point which is equidistant from the points A(0,2,3) and B(2,-2,1)