A projectile is fired with velocity u at an angle `theta` with horizontal. At the highest point of its trajectory, it splits up into three segments of masses m, m and 2m. First part falls vertically downward with zero initial velocity and second part returns via same path to the point of projection. The velocity of third part of mass 2 m just after explosion will be

A projectile of mass 20 kg is fired with a velocity of 400m//s at an angle of 45^(@) with the horizontal .At the highest point of the trajectocy the projectile explodes into two fragments of equal mass,one of which falls vertically downward with zero initial speed, The distance of the point where the other fragment falls from the point offiring is:

A shell of mass 2m fired with a speed u at an angle theta to the horizontal explodes at the highest point of its trajectory into two fragments of mass m each. If one fragment falls vertically, the distance at which the other fragment falls from the gun is given by :

A particle of mass m is projected with a velocity mu at an angle of theta with horizontal.The angular momentum of the particle about the highest point of its trajectory is equal to :

A projectile of mass mis fired with an initial velocity v_(0) at an angle 0 to the horizontal. At its highest point, it explodes into two fragments of equal mass. One of the fragments falls vertically with zero initial speed. Since the only external force acting on the system is gravitational, the motion of centre of mass of the_ system (the fragments) follows the same parabolic path as the projectile would have followed if there had been no explosion. Force of explosion is internal, it cannot change the trajectory of the system.

A particle is projected with a velocity 200 m//s at an angle of 60^(@). At the highest point it explodes into three particle of equal masses. One goes vertically upward with a veloctiy 100m//s the second particle goes vertically downwards at same speed. What is the velocity of the third particle?

A particle is projected with velocity 'u' makes an angle theta w.r.t. horizontal. Now it breaks in two identical parts at highest point of trajectory. If one part is retrace its path, then velocity of other part is -

A particle of mass m is projected with velocity v at an angle theta with the horizontal. Find its angular momentum about the point of projection when it is at the highest point of its trajectory.

A 24-kg projectile is fired at an angle of 53^(@) above the horizontal with an initial speed of 50m//s . At the highest point in its trajectory, the projectile explodes into two fragments of equal mass, the first of which falls vertically with zero initial speed. (a) How far from the point of firing does the second fragment strike the ground? (Assume the ground is level.) (b) How much energy was released during the explosion?