Morning breakfast gives "5000" cal to a 60kg person.The efficiency of person is 30%.The efficiency of person is 30% .The height upto which the person can climb up by using energy obtained from breakfast is

Morning breakfast gives 5000 cal to a 60 kg person.The efficiency of person is 30%. The height upto which the person can climb up by using energy obtained from breakfast is

Morning breakfast gives 5000 cal to a 60 kg person.The efficiency of person is 30% .The height upto which the person can climb up by using energy obtained from breakfast is

Morning breakfast gives 5000 cal to a 60 kg. person. The efficiency of person is 30%. The height upto which the person can climb up by using energy obtained from breakfast is

A bread gives a boy of mass 40 kg an energy of 21 kJ. If the efficiency is 28%, then the height that can be climbed by him using this energy, is :

A worker eats a dish of icecream which funishes 200 kcal of heat. If the efficiency of the body is 25%, then calculate the height to which the worker can carry a weight of 56 kg using the energy of icecream. Worker's own weight is 70 kg. Given J = 4.2 J cal^(-1) .

A man of 60kg gains 1000 cal of heat by eating 5 mangoes. His efficiency is 56%. To what height he can jump by using this energy?

A man of 60 kg gains 1000 cal of heat by eating 5 mangoes. His efficiency is 29% . To what height he can jump by using this energy?

The weight of a person is 60 kg . If he gets 10 calories of heat through food and the efficiency of his body is 28% , then upto what height he can climb? Take g = 10m s^(-2)

The weight of a person is 60 kg . If he gets 105 calories heat through food and the efficiency of his body is 28%, then upto how much height he can climb (approximately)