In \(ICl_{3}\),hybridization of I is \(sp^{x}d^{y}\) and number of lone pairs on "|" are "z. x+y+z is

In \(ICl_{3}\) the total number of lone pairs is x. In \(ClO_{2}^{-}\) lone pairs on Cl is y. The oxidation state of lodine in IBr is z. then (x+z)/y is

1) The number of \(SP^{3}\) hybridised "C" atoms in p-nitro acetanilide is x 2) The number of lone pairs at Nitrogen atom in p -nitro acetanilide is y What is \((\frac{2x+y}{3})\)

" In triplet \(CH_{2}\) ,the number of hybrid orbitals involved are "X" ,and the number of lone pairs present on Carbon are "Y" .The value of "X+Y" is "

In IF_3 . Hybrid state of iodine is sp^3 d . There are two lone pair and three bondpairs of electron. Lone pair electorn is positioned on :

xyz=24 , x,y,z in N. Then find the number of order pairs (x,y,z)

Calculate x+y+z for H_(3)PO_(3) acid, where x is number of lone pairs, y is number of sigma -bonds and z is number of pi -bonds

Compound formed by sp^(3)d hybridization with no lone pair will have structure

Number of lone pair - bond pair repulsion at 90^(@) are (P) in I_(3)^(-) . Number of lone pair - bond pair repulsion at 90^(@) are (Q) in ICl_(4)^(-) .Find difference of (P) and (Q)

Count the total number of unshared electrons on I_(3)^(-)=3 Count the total number of ppi-dpi bonds in PO_(4)^(3-)=y Count the total number of lone pairs in XeF_(4)=z Hence, find the value of x-z-y

The number of solutions of equations x+y-z=0,3x-y-z=0,x-3y+z=0 is