A body freely released from A slides down a smooth inclined plane 'AB' and then a rough incline plane 'BC' such that BC = N (AB). If the block comes to rest at C, then coefficient of kinetic friction between the block and inclined plane is?

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

A block is placed on an inclined plane. The angle of inclination of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is

A block sliding down on a rough 45^(@) inclined planes has half the velocity it would have been, the inclined plane is smooth. The coefficient of sliding friction between the the block and the inclined plane is

A block of mass m takes time t to slide down on a smooth inclined plane of angle of inclination theta and height h. If same block slids down on a rough inclined plane of same angle of inclination and same height and takes time n times of initial value, then coefficient friction between block and inclined plane is

Starting from rest , a body slides down at 45^(@) inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of friction between the body and the inclined plane is

A block kept on a rough inclined plane ,as shown in the figure, remains at rest upto a maximum force 2N down the inclined plane. The maximum external force up the inclined plane that does not move the block is 10N .The coefficient of static friction between the block and the palbe is : [Taking g=10m//s^(2) ].

A block is at rest at the top of a rough inclined plane of inclination 30° with the horizontal. What is the coefficient of kinetic friction between the block and the plane, if the . block slides down with an acceleration of g/5 ?