If `x=t+(1)/(t)` and `y=t-(1)/(t)`, where t is a parameter,then a value of `(dy)/(dx)`

A curve is represented paramtrically by the equations x=e^(t)cost and y=e^(t)sint where t is a parameter. Then The value of (d^(2)y)/(dx^(2)) at the point where t=0 is

If x=a(t-(1)/(t)),y=a(t+(1)/(t)) , where t be the parameter, then (dy)/(dx)=?

If x = e^(t) sin t and y = e^(t) cos t, t is a parameter , then the value of (d^(2) x)/( dy^(2)) + (d^(2) y)/(dx^(2)) at t = 0 , is :

A curve in the xy-plane is parametrically given by x=t+t^(3) and y=t^(2), where t in R is the parameter.For what value (s) of t is (dy)/(dx)=(1)/(2)?(1)/(3) b.2 c.3 d.1

Let x=2(t+(1)/(t)) and y=2(t-(1)/(t)),t!=0. Then,the value of (dy)/(dx) at t=2 is

If x=(t+1)/(t),y=(t-1)/(t)," then "(dy)/(dx)=

If x=(t+1)/(t),y=(t-1)/(t)," then: "(dy)/(dx)=

If x=(t+(1)/(t)),y=(t-(1)/(t)) , then (dy)/(dx)=?

If x=t+(1)/(t),y=t-(1)/(t)," where "tne0," then: "(d^(2)y)/(dx^(2))=

If tan x = (2t)/(1 -t^(2)) " and sin y" = (2t)/(1 + t^(2)) , then the value of (dy)/(dx) is