The point to which origin is shifted in order to miss the first degree terms in `2x^(2)+5xy+3y^(2)+6x+7y+1=0` is (h,k) then
(A) h+k=-1 (B) 2h+k=0 (c) h+k=1 (D) h+k=-2

If (1, k) is the point of intersection of the lines given by 2x^(2)+5xy+3y^(2)+6x+7y+4=0 , then k=

If the image of the point (1,2,3) in the plane x+2y=0 is (h,k,l) then l=

When the origin is shifted to the point (5,-2) then the transformed equation of the curve xy+2x-5y+11=0 is XY=K then k is

The centre of circle 2x^(2)+2y^(2)+30x+40y+3=0 is (h,k) then the value of h+k is equal

If the system of linear equations x-4y+7z=g,3y-5z=h-2x+5y-9z=k is consistent,then (a) g+2h+k=0 (b) g+h+2k=0(c)2g+h+k=0 (d) g+h+k=0

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , then therm containing linear powers are missing, then point (h, k) is

The orthocentre of triangle formed by lines x+y-1=0, 2x+y-1=0 and y=0 is (h, k), then (1)/(k^(2))=