v20.2

A capacitor of capacitance C = 2.0 +- 0.1 mu F is charged to a voltage V = 20+- 0.2 V . What will be the charge Q on the capacitor ? Use Q = CV .

The velocity of a body depends on time according to the equation v=(t^(2))/(10)+20 . The body is undergoing

The resistance R = (V )/(i) , where V=(50 pm 2.0)V and I=(20pm 0.2)A. The percentage error in R is ’x’% The value of 'x' to the nearest integer is "_________"

The resistance R=(V)/(I) where V=(200+-5)V and I=(20+-0.2)A ,the percentage error in the measurement of "R" is :

A vessel of volume V = 7.51 contains a mixture of ideal gases at a temperature T = 300 K : v_1 = 0.10 mole of oxygen, v_2 = 0.20 mole of nitrogen, and v_3 = 0.30 mole of carbon dioxide. Assuming the gases to be ideal, find : (a) the pressure of the mixture , (b) the mean molar mass M of the given mixture which enters its equation of state p V = (m//M) RT , where m is the mass of the mixture.

The volume of oxygen gas liberated at NTP from 30 mL of 20 (V H_2O_2) , solution is

Calculate the values of gamma = C_p//C_v for a gaseous mixture consisting of v_1 = 2.0 moles of oxygen and v_2 = 3.0 mole of carbon dioxide. The gases are assumed to be ideal.