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If 4cos theta-3sec theta=2tan theta then...

If `4cos theta-3sec theta=2tan theta` then `theta=` (A) "n pi+(-1)^(n)(pi)/(10),,,n in z],[" (B) "n pi+(-1)^(n)(pi)/(6),n in z],[" (c) "n pi-(-1)^(n)(3 pi)/(10),n in z],[" (D) "n pi,n in z]]

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