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The decomposition of ethane follows the ...

The decomposition of ethane follows the rate law \(\frac{-d[CH_{3}CH_{3}]}{dt}\)=K\([C_{2}H_{6}\) with overall \(K=(\frac{K_{1}K_{2}K_{3}K_{4}}{K_{5}})^{1/2}\) where \(K_{1},K_{2},K_{3},K_{4},K_{5}\)are the rate constants of various elementary steps.The values of \(E_{a}\) of elementary reactions were found to be
\(E_{a_{1}}\)=350kJ/mol
\(E_{a_{2}}\)=2kJ/mol],
\(E_{a_{3}}\)=160kJ/mol],
\(E_{a_{4}}\)=30kJ/mol],
\(E_{a_{5}}\)=10kJ/mol]
The activation energy of the overall reaction is x kJ/mol.The value of x/5 is

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