Two circles are drawn as OA and OB as diameters,where O is origin,A is (-4,6) and B is (8,4) .Then the length of common chord of the circles is `(a)/(sqrt(b)` where b-a equals

Two circles of equal radius of 5 units have their centres at the origin and the point (2, -3). Equation of the common chord of these circles is

Two equal circles intersect such that each passes through the centre of the other. If the length of the common chord of the circles is 10sqrt3 cm, then what is the diameter of the circle?

ABDC is a circle and circles are drawn with AO, CO, DO and OB as diameters. Areas X and Y are shaded X/Y is equal to

In the adjoining figure, A and B are the centres of two circles. If CB=17cm, EB=15cm, then find the length of common chord.

Points A(a) and B (b) are on xy = 1 , Circles with OA and OB as diameter, where O is the origin are drawn to intersect at p , then OP intersects the curve at

Two concentric circles of radii a and b(a gt b) are given. Find the length of the chord of the larger circle which touches the smaller circle.

Two circles whose radii are equal to 4 and 8 intersect at right angles.The length of their common chord is-

Let B and C lie on the circle with OA as a diameter,where O is the origin. If AOB = BOC = theta and z_1, z_2, z_3, representing the points A, B, C respectively,then which one of the following is true?