Two S.H.M.s along the same straight line in the same direction and of the same period are given by the equations, `x_1=3" "sin(4pit+pi/6)` and `x_2=4" " sin(4pit+pi/3)`. The initial phase of the resultant motion is

Two parallel S.H.M.s have equations y_1=A_1sin(omegat+2pi) and y_2=A_2sin(omega/t+4pi) . The amplitude of the resultant motion is

Two SHW are represented by the equations x_1 = 20 sin [5pit +pi/4] and x_2 = 10 (sin5pit+sqrt(3) cos 5 pit] . The ratio of the amplitudes of the two motions is

An SHM is given by the equation x = 8 sin (4 pi t) + 6 cos (4pit)] cm find its amplitude and period

Two simple harmonic motions are represented by the equations y_(1) = 10 sin(3pit + pi//4) and y_(2) = 5(sin 3pit + sqrt(3)cos 3pit) their amplitude are in the ratio of ………… .

Two simple harmonic motions are represented by the equations x_1=5sin(2pit+pi/4) and x_2=5sqrt2(sin2pit+cos2pit) .The amplitude of second motion is ____ times the amplitude in first motion.

x_1=5/2[sin(2pit)+ cos(2pit)] , x_2=5[sin(2pil+pi/4)] Find the ratio of amplitude of the given motion ?

Two simple harmonic motions are represented by the equations y_(1) = 10 sin (3pit + (pi)/(4)) and y_(2) = 5 (3 sin 3 pi t+sqrt(3) cos 3 pi t) . Their amplitudes are in the ratio of

Two particles of a medium disturbed by the wave propagtion are at x_(1)=0 and x_(2)=1 cm The wave is propagating in positive x-direction The displacement of the particles is given by the equation: y_(1)=(2sin3pit) cm and y_(2)=2sin(3pit-pi//8) cm (t is in seconds)

Two particles are executing S.H.M. according to the equations x_(1)=6sin(10pit+pi//3)andx_(2)=6cos(8pit+pi//4) Then the phase difference between the first and second particle at t = 0.5 s will be