If the centroid and two vertices of a triangle are `(4.-8),(-9,7),(1,4)` respectively. Then the area of the triangle ( in sq.units) is

If the centroid and two vertices of a triangle are (4,-8),(-9,7),(1,4) then the area of the triangle (in sq.units ) is a(b)/(c) then (a)/(83)=

If the centroid and two vertices of a triangle are (4,-8),(-9,7),(1,4) and the area of the triangle (in sq.units) is "K" ,then (8)/(333)K is equal to

In Fig.3, the area of triangle ABC( in sq.units ) is :

If the area of the triangle is 4sq units, then x is

If the centroid of a triangle is (1,4) and two of its vertices are (4,-3) and (-9,7) , then the area of the triangle is 183 sq.units (b) (183)/(2) sq.units (c)366 sq.units (d) (183)/(4) sq. units

If (1,4) is the centroid of a triangle and the coordinates of its any two vertices are (4,-8) and (-9,7), find the area of the triangle.

if the vertices of a triangle are (1,-3)(4,p)(-9,7) and its are area 15 Squnits then find the value of P

The vertex of the right angle of a right angled triangle lies on the straight line 2x-y-10=0 and the two other vertices, at points (2,-3) and (4,1) then the area of triangle in sq.units is-