If `a^(x)=bc,b^(y)=ca,c^(z)=ab` where `a,b,c>0,` then `(x)/(1+x)+(y)/(1+y)+(z)/(1+z)`

If a^(x-1)=bc,b^(y-1)=ca,c^(z-1)=ab, then sum((1)/(x))=

If a^(x)=b, b^(y)=c, c^(z)=a , then what is the value of (1)/((xy+yz+zx))((1)/(x)+(1)/(y)+(1)/(z)) ?

If a^(x-1)=bc,b^(y-1)=ca,c^(z-1)=ab, and (xy+yz+zx)/(xyz)=k, then find K

a^(x)=b^(y)=c^(z) and b^(2)=ac then prove that (1)/(x)+(1)/(z)=(2)/(y)

If x = log_(a) bc, y = log_(b) ca, z = log_(c) ab, then the value of (1)/(1 + x) + (1)/(1 + y) + (1)/(l + z) will be

If a^(x)=b^(y)=c^(z)andabc=1 , then the value of 1/(x)+1/(y)+1/(z) will be equal to

if a,b,c are in G.P. and a^(x)=b^(y)=c^(z) prove that (1)/(x)+(1)/(z)=(2)/(y)