A particle is projected from a point P with a velocity v at an angle `theta` with horizontal. At a certain point Q it moves at right angles to its initial direction. Then

A particle is projected from a point O with a velocity u at an angle alpha (upwards) to the horizontal. At a certain point P it moves at right angles to its initial direction. It follows that:

A particle is project d from point A with velocity u at an angle alpha with horizontal. In its parabolic path, at point P the particle is moving at right angles to its initial direction of projection. Its velocity at P is:

A particle is projected form ground with velocity u ar angle theta from horizontal. Match the following two columns.

A particle is projected from the ground with an initial speed v at an angle theta with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is [EAM 2013]

A particle is projected from the ground with an initial speed of v at an angle theta with horizontal. The average velocity of the particle between its point of projection and highest point of trajectroy is :

A particle is projected with a velocity u making an angle theta with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

A particle is projected from a point A with velocity usqrt2 at an angle of 45^(@) with horizontal as shown in the figure. It strikes the plane BC at right angles. The velocity of the particle at the time of collision is

A particle is projected with velocity v at an angle theta aith horizontal. The average angle velocity of the particle from the point of projection to impact equals