The force F acting on a body varies with its displacement x as `F=Kx^(2/3)` .The power delivered by the force will be proportional to?

A force F acting on a body depends on its displacement x as Fpropx^(a) . The power delivered by F will be independent of x if n is -

A force F acting on a body depends on its displacement S as FpropS^(-1//3) . The power delivered by F will depend on displacement as

A force Facting on a body depends on its displacement 'S' as F∝ s^(-(1)/(3) .The power delivered by F will depend on displacement as

A force (F) acting on a body is dependent on its desplacement s. as Fprops^(-1//3) . Therefore , the power delivered by the force varies with its displacment as

A variable force F acts on a body which is free to move. The displacement of the body is proportional to t^(3) , where t = time. The power delivered by F to the body will be proportional to

A force F acting on an object varies with distance x The work done by the force in moving the object from x=0 to x=8 m is

A force F acting on an object varies with distance x as shown in the figure. The work done by the force in moving the object from x=0 to x = 20 m is

A force F=(3thati + 5hatj)N acts on a body due to which its displacement varies as S=(2t^(2)hat-5hatj)m . Work done by these force in 2 s is .