In amalgams of metal,Oxidation state of Mercury is

The number of mercury atoms in iodide of Millons base is x and the oxidation state of each mercury atom is y. Then (x+y) is

The number of mercury atoms in iodide of Millons base is x and the oxidation state of each mercury atom is y. Then (x+y) is

Assertion:Amalgam of mercury with sodium is an example of solid solutions . Reason:Mercury is solvent and sodium is solute in the solution

Transition metals exhibit variable oxidation states. It is because of

In which of the following complexes oxidation state of metal is zero