A partical of mass `2kg` is moving on the `x-`axis with a constant mechanical energy `20 J`. Its potential energy at any `x` is `U=(16-x^(2))J` where `x` is in metre. The minimum velocity of particle is `:-`

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is

The total mechanical energy of a 2.00 kg particle moving along an x axis is 5.00 J. The potential energy is given as U(x)=(x^(4)-2.00x^(2))J , with x in meters. Find the maximum velocity.

A particle of mass 2 kg moving along x-axis has potential energy given by, U=16x^(2)-32x ( in joule), where x is in metre. Its speed when passing through x=1 is 2ms^(-1)

A particle of mass m is executing osciallations about the origin on the x-axis with amplitude A. its potential energy is given as U(x)=alphax^(4) , where alpha is a positive constant. The x-coordinate of mass where potential energy is one-third the kinetic energy of particle is

A particle is constrained to move in the region x ge 0 and its potential energy is given by U=2x^(4)-3x^(2)J (where x is in m) For what values of x, the particle is under Unstable equilibrium

A particle is constrained to move in the region x ge 0 and its potential energy is given by U=2x^(4)-3x^(2)J (where x is in m) For what values of x, the particle is under Stable equilibrium

The potential energy of a partical of mass 2 kg moving in y-z plane is given by U=(-3y+4z)J where y and z are in metre. The magnitude of force ( in newton ) on the particle is :

Potential energy of a particle along x-axis varies as U = - 30 + (X-2)^2 , where U is in joule and x is in meter. Hence the particle is in

A particle of mass m is moving in a potential well, for which the potential energy is given by U(x) = U_(0)(1-cosax) where U_(0) and a are positive constants. Then (for the small value of x)