The decomposition of ethane follows the ...

The decomposition of ethane follows the rate law `(-d[CH_(3)CH_(3)])/(dt)=K[C_(2)H_(6)]` with overall K=`((K_(1)K_(2)K_(3)K_(4))/(K_(5)))` , where `K_(1),K_(2),K_(3),K_(4),K_(5)` are the rate constants of various elementary steps.The values of `E_(a)` of elementary reactions were found to be
`E_(a_(1))=350(kJ)/(mol ) `
`E_(a_(2))=2 (kJ)/(mol)`
`E_(a_(3))=160(kJ)/(mol) `
`E_(a_(4))=30(kJ)/(mol)`, `E_(a_(5))=10(kJ)/(mol)`
The activation energy of the overall reaction is xkJ/mol. The value of `(x)/(5)` is

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