The values of `ba n dc` for which the identity of `f(x+1)-f(x)=8x+3` is satisfied, where `f(x)=b x^2+c x+d ,a r e` `b=2,c=1` (b) `b=4,c=-1` `b=-1, c=4` (d) `b=-1,c=1`

If f(x) =ax^(2) + bx + c satisfies the identity f(x+1) -f(x)= 8x+ 3 for all x in R Then (a,b)=

If f'(c)=(f (b)-f(a))/(b-a) , where f(x) =e^(x), a=0 and b=1 , then: c = ….

The values of the constants a , ba n dc for which the function f(x)={(1+a x)^(1//x)b ,x 0x=0 may be continuous at x=0, are a=(log)_e(2/3),b=-2/3,c=1 a="log")e (2/3),b2/3,c=-1 a=(log)_e(2/3),b=2/3,c=1 (d) none of these

The number of points at which g(x)=(1)/(1+(2)/(f(t))) is not differentiable,where f(x)=(1)/(1+(1)/(x)), is 1 b.2 c.3d.4

f(x)={(x-4)/(|x-4|a+b)+a,x 0 Then,f(x) is continuous at x=4 when (a) a=0,b=0 (b) a=1,b=1(c)a=-1,b=1(d)a=1,b=-1

The value of f(1) so that the function f(x)=(1-cos(1-cos x))/(x^(4)) is continuous everywhere is (A) (1)/(2)(B)(1)/(4)(C)(1)/(8)(D)2

If x!=1\ a n d\ f(x)=(x+1)/(x-1) is a real function, then f(f(f(2))) is (a) 1 (b) 2 (c) 3 (d) 4

f(x)={(x-4)/(|x-4|)+a,x 4 Then f(x) is continous at x=4 when a.a=0,b=0 b.a=1,b=1 c.a=-1,b=1 d.a=1,b=-1

The mean value theorem is f(b) - f(a) = (b-a) f'( c) . Then for the function x^(2) - 2x + 3 , in [1,3/2] , the value of c: