[" 16"((2x+3)-15x-7))/(6x+11)=-(8)/(3)],[hline]

((2x + 3) - (5x-7)) / (6x + 11) = (8) / (3)

Solve the equation and verify your answer: ((2x+3)-\ (5x-7))/(6x+11)=\ -8/3

Solve the equation and verify your answer: ((2x+3)-\ (5x-7))/(6x+11)=\ -8/3

(3x+8)/16-((12x-6)/(15x-30))+x/3=(7x)/12-((2x+16)/32)

If 15(2)/(3) xx 3(1)/(6) +6(1)/(3)=11(7)/(8) +x , then the denominator of x in simplest form is

5x-(3x-7)-{4-2(6x-3)}=11

Solve : (7x +3)/(4) + (9x -5)/(8) = (16x-3)/(16) The following steps are involved in solving the above problem. Arrange them in sequential order (A) x = (-5)/(30) = (-1)/(6) (B) (7x + 3)/(4) + (9x -5)/(8) = (16x-3)/(16) rArr (14x + 6 + 9x -5)/(8) = (16x -3)/(16) (C) (23x + 1)/(8) = (16x -3)/(16) rArr 23x + 1 = (16x -3)/(2) (D) 46x + 2 = 16x - 3 rArr 30 x = -5

[" 8"," I "],[" M ",(1)/(*)],[,(4)/(4)],[,(9)/(2)],[,(9)/(9)],[,9],[hline,(4)/(3)],[+,9],[hline,1],[,7],[,3],[,9],[hline,1],[hline,-,(1)/(3)],[,,]