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[(k-1)u-y=5],[(k+1)x+(1-k)y=(3k+1)]...

[(k-1)u-y=5],[(k+1)x+(1-k)y=(3k+1)]

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Find the value of k for which the system of equation (k-1)x-y=5,(k+1)x+(1-k)y=(3k+1) has infinite no of solution

Find the value k if the following equations are consistent (k+1)x+(k-1)y+(k-1)=0,(k-1)x+(k+1)y+(k-1)=0,(k-1)x+(k-1)y+(k+1)=0

( k - 1 ) x - y = 5 , (k + 1 ) x + ( 1 - k ) y = ( 3k + 1 )

The number of values of k for which the system of equations: kx+(3k+2)y=4k (3k-1)x+(9k+1)y=4(k+1) has no solution, are

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The number of values of k for which the system of equations: kx+(3k+2)y=4k (3k-1)x+(9k+1)y=4(k+1) has no solution, are

Find the value k if the following equations are consistent (k-2)x+(k-1)y=17,(k-1)x+(k-2)y=18 and x+y=5

{:(2x + 3y = 2),((k + 2)x + (2k + 1)y = 2(k - 1)):}