[px+2y=5],[cx+y=1]

The pair of linear equations px+2y=5 and 3x+y=1 has unique solution if

The plane which passes through the point (3,2,0) and the line (x-3)/(1)=(y-6)/(5)=(z-4)/(4) is a.x-y+z=1 b.x+y+z=5cx+2y-z=1d.2x-y+z=5

The differential equation x(dy)/(dx)-y=x^(2), has the general solution y-x^(3)=2cx b.2y-x^(3)=cx c.2y+x^(2)=2cx d.y+x^(2)=2cx

The differential equation which represents the family of curves y=e^(Cx) is y_(1)=C^(2)y b.xy_(1)-In y=0 c.x In y=yy_(1) d.y In y=xy_(1)

If the lines 2x+3y=8,5x-6y+7=0 and px+py=1 are concurrent,then the line x+2y-1=0 passes through

Prove that [[x, x^2 , 1+px^3], [y, y^2, 1+py^3] ,[z, z^2, 1+pz^3]] = (1+pxyz)(x-y)(y-z)(z-x)

Find the value of p if the lines 3x+4y=5, 2x+3y=4, px+4y=6 are concurrent.