=(27)^(2/3)-:(27)^(5/3)

Evaluate : (27)^(-(1)/(3)).(27)^(-(1)/(3))[(27)^((1)/(3))-(27)^((2)/(3))]

Simplify: ((27)^((-2)/(3)))/((27)^((-1)/(3)))

The value of 27^(-1//3) xx [27^(2//3) + 27^(1//3)] is

Solve ((0.73)^(3)+(0.27)^(3))/((0.73)^(2)+(0.27)^(2)-0.73xx0.27)=?(a)0.27(b)0.4087(c)0.73(d)1

Simplify 27^((1)/(3))[27^((1)/(3))-27^((2)/(3))]

Simplify : 27^(-(1)/(3))(27^((1)/(3))-27^((2)/(3)))

(9^(n)xx3^(2)xx3^(n)-(27)^(n))/((3^(3))^(5)xx2^(3))=(1)/(27)

If S=1^(27)+2^(27)+3^(27)+4^(27)+......+199^(27) and a,b are unit digit and digit at ten's place of S then a+b is equals to