[" If "A=([1,tan(theta/2)],[-tan(theta/2),1])" and "],[AB=I," then "B=?]

If A = [(1,tan""(theta)/(2)),(-tan""(theta)/(2),1)] and AB = I_(2) , then B=

If A = [(1,-tan""(theta)/(2)),(tan""(theta)/(2), 1)] and B = [(1,tan""(theta)/(2)),(-tan""(theta)/(2), 1)] show that, AB^(-1) = [(costheta,-sin theta),(sin theta, cos theta)] .

If A(theta)=[(1, than theta),(-tan, theta=1)] and AB=l , then (sec^(2)theta)B is equal to

[[1, -tan((theta)/(2))], [tan((theta)/(2)), 1]][[1, tan((theta)/(2))], [-tan((theta)/(2)), 1]]^(-1)=

Show that [[cos theta,-sin theta],[sin theta,cos theta]]=[[1,-tan(theta)/(2)],[tan(theta)/(2),1]][[1,tan(theta)/(2)],[-tan(theta)/(2),1]]^(-1)

A = [(0,-tan""(theta)/(2)),(tan""(theta)/(2),0)] and (I+A)(I-A)^-1=[(a,-b),(b,a)] . Find 13(a^2+b^2)

Show that [[1 , -tan theta ],[ tan theta, 1]][[1, tan theta],[ -tan theta, 1]]^(-1)=[[cos 2 theta, -sin 2 theta],[ sin 2 theta, cos 2 theta]]

If "tan" 2 theta "tan" theta =1, "then" theta =