(cosec^(2)(90^(@)-theta)-tan^(2)theta)/(2(cos^(2)48^(@)+cos^(2)42^(@)))-(2tan^(2)30^(@)sec^(2)52^(@)sin^(2)38^(@))/(cosec^(2)70^(@)-tan^(2)20^(@))

Without using trigonometric table,evaluate the following: (cos ec^(2)(90-theta)-tan^(2)theta)/(4(cos^(2)48^(@)+cos^(2)42^(@)))-(2tan^(2)30^(@)sec^(2)52^(@)sin^(2)38^(@))/(cos ec^(2)70^(@)-tan^(2)20^(@))

Without using trigonometric table, evaluate the following: (cosec^2(90-theta)-tan^2theta)/(4(cos^2 48^@+cos^2 42^@))-(2tan^2 30^@ sec^2 52^@ sin^2 38^@)/(cosec^2 70^@-tan^2 20^@

tan^(2)(90^(@) - theta) - cosec^(2) theta =

tan^(2)(90^(@) - theta) - cosec^(2) theta =

(sec^(2)theta-sin^(2)theta)/(tan^(2)theta)=cosec^(2)theta-cos^(2)theta

Choose the correct answer in each of the following questions: (2tan^(2)30^(@)sec^(2)52sin^(2)38^(@))/("cosec"^(2)70^(@)-tan^(2)20^(@))=?

Write the value of "cosec"^(2)(90^(@)-theta)-tan^(2)theta.

(tan(90^@-theta) cot theta)/(cosec^2 theta)-cos^2 theta=0

Evaluate: (sec theta csc(90^(0)-theta)-tan theta cot(90^(0)-theta)+sin^(2)55^(0)+sin^(2)35^(@))/(tan10^(0)tan20^(0)tan60^(@)tan70^(0)tan80^(0))