[" (i) "x^(3)-2x^(2)-x+2," (ii) "x^(3)-3x^(2)-9x-5],[" (iii) "x^(3)+13x^(2)+32x+20," (iv) "2y^(3)+y^(2)-2y-1]

Factorise: (i) x^(3)-2x^(2)-x+2 (ii) x^(3)-3x^(2)-9x-5 (iii) x^(3)+13x^(2)+32x+20 (iv)

Factorise (i) x ^(2) - 2x ^(2) - x +2 (ii) x ^(3) - 3x ^(2) - 9x -5 (iii) x ^(3) + 13 x ^(2) + 32 x + 20 (iv) y ^(3) + y ^(2) -y -1

Factorise: (i) x^3-2x^2-x+2 (ii) x^3-3x^2-9x-5 (iii) x^3+13 x^2+32 x+20 (iv) 2y^3+y^2-2y-1

The solution of (dy)/(dx)+(3)/(x)y=(1)/(x^(2)), given that y=2,x=1 is (i) 2x^(3)y=x^(2)-3( ii) 2x^(3)y=x^(2)+3( iii) x^(3)y=x^(2)+3( iv )2x^(3)y=x^(2)+5

Factorize following expressions (i) x^(3)-6x^2+11x-6 " (ii)" 2x^3+9x^2+10x+3 (iii) 2x^3-9x^2+13x-6" (iv)" x^6-7x^2-6

{:("Column" A ,, "Column" B), ((3x^(2) - 5)- (2x^(2) - 5 + y^(2)) ,, (a) x^(2) + xy + y^(2)) , (9x^(2) - 16y^(2) ,, (b) 2) , ((x^(3) - y^(3))/(x-y) ,, (c) (9x + 16y) (9x - 16y)) , ("The degree of " (x + 2) (x+3) ,, (d) x^(2) - y^(2)) , (,, (e) 1) , (,, (f) (3x + 4y) (3x - 4y)):}

x-y relation is given by y=x^(n) calculate the value of n in the following :- (i) y=(x^(2))/(x^(2//3)) (ii) y=(x^(3//2))/(x^(1)) (iii) y=(x^(1//2))/(x^(1//2)) (iv) y=(x^(3//2))/(sqrt(x))

x-y relation is given by y=x^(n) calculate the value of n in the following :- (i) y=(x^(2))/(x^(2//3)) (ii) y=(x^(3//2))/(x^(1)) (iii) y=(x^(1//2))/(x^(1//2)) (iv) y=(x^(3//2))/(sqrt(x))