10 mol of Zn react with 10 mol of HCl. Calculate the number of moles of `H_(2)` produced.

Options

A. 5 mol
B. 10 mol
C. 20 mol
D. 2.5 mol

Answer

To determine the number of moles of \( H_2 \) produced when 10 moles of Zn react with 10 moles of HCl, we can follow these steps:

### Step 1: Write the balanced chemical equation

The reaction between zinc (Zn) and hydrochloric acid (HCl) can be represented by the following balanced equation:

\[ \text{Zn} + 2 \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2 \]

### Step 2: Identify the mole ratio from the balanced equation

From the balanced equation, we can see that:
- 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of \( H_2 \).

### Step 3: Determine the limiting reactant

In this case, we have:
- 10 moles of Zn
- 10 moles of HCl

To find out which reactant is limiting, we can use the mole ratio:
- For 10 moles of Zn, we would need \( 10 \times 2 = 20 \) moles of HCl.
- However, we only have 10 moles of HCl available.

Thus, HCl is the limiting reactant.

### Step 4: Calculate the moles of \( H_2 \) produced

Since HCl is the limiting reactant, we can calculate the moles of \( H_2 \) produced based on the amount of HCl available:
- From the balanced equation, 2 moles of HCl produce 1 mole of \( H_2 \).
- Therefore, 10 moles of HCl will produce:

\[ \text{Moles of } H_2 = \frac{10 \text{ moles of HCl}}{2} = 5 \text{ moles of } H_2 \]

### Conclusion

The number of moles of \( H_2 \) produced is **5 moles**.

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