`{:(" Column X "," Column Y "),("a. Petrol ","i. Heterogenous mixture "),("b. Graphite ","ii. Compound "),("c. Sucrose ","iii. Element "),("d. Milk ","iv. Hamogeneous mixture "),(,):}`

Answer

To solve the problem of matching items from Column X to Column Y, we will analyze each item in Column X and determine its classification based on the definitions provided in Column Y.

### Step-by-Step Solution:

1. **Identify the items in Column X**:
- a. Petrol
- b. Graphite
- c. Sucrose
- d. Milk

2. **Identify the classifications in Column Y**:
- i. Heterogeneous mixture
- ii. Compound
- iii. Element
- iv. Homogeneous mixture

3. **Match each item from Column X with the appropriate classification in Column Y**:

- **a. Petrol**:
- Petrol is a mixture of various hydrocarbons that are uniformly mixed together. Therefore, it is classified as a **homogeneous mixture**.
- **Match**: a → iv (Homogeneous mixture)

- **b. Graphite**:
- Graphite is composed entirely of carbon atoms and is considered an element. Therefore, it is classified as an **element**.
- **Match**: b → iii (Element)

- **c. Sucrose**:
- Sucrose is a chemical compound made up of carbon, hydrogen, and oxygen. Therefore, it is classified as a **compound**.
- **Match**: c → ii (Compound)

- **d. Milk**:
- Milk contains water and fat, which do not mix completely, making it a **heterogeneous mixture**.
- **Match**: d → i (Heterogeneous mixture)

4. **Final Matching**:
- a → iv (Petrol → Homogeneous mixture)
- b → iii (Graphite → Element)
- c → ii (Sucrose → Compound)
- d → i (Milk → Heterogeneous mixture)

### Summary of the Matches:
- a. Petrol → iv. Homogeneous mixture
- b. Graphite → iii. Element
- c. Sucrose → ii. Compound
- d. Milk → i. Heterogeneous mixture