How many oxygen atoms are present in 16 g of ozone (`O_(3)`)?

Answer

To find out how many oxygen atoms are present in 16 g of ozone (O₃), we can follow these steps:

### Step 1: Determine the molar mass of ozone (O₃)
The molar mass of ozone can be calculated as follows:
- The atomic mass of oxygen (O) is approximately 16 g/mol.
- Since there are three oxygen atoms in one molecule of ozone (O₃), the molar mass of ozone is:

\[ \text{Molar mass of O}_3 = 3 \times 16 \, \text{g/mol} = 48 \, \text{g/mol} \]

### Step 2: Calculate the number of moles of ozone in 16 g
To find the number of moles of ozone in 16 g, we use the formula:

\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

Substituting the values:

\[ \text{Number of moles of O}_3 = \frac{16 \, \text{g}}{48 \, \text{g/mol}} = \frac{1}{3} \, \text{mol} \]

### Step 3: Calculate the number of oxygen atoms in the moles of ozone
Each mole of ozone contains 3 moles of oxygen atoms. Therefore, the number of moles of oxygen atoms in \(\frac{1}{3}\) moles of ozone is:

\[ \text{Number of moles of O} = 3 \times \frac{1}{3} \, \text{mol} = 1 \, \text{mol} \]

### Step 4: Convert moles of oxygen to number of atoms
Using Avogadro's number (\(6.02 \times 10^{23}\) atoms/mol), we can find the number of oxygen atoms:

\[ \text{Number of oxygen atoms} = 1 \, \text{mol} \times 6.02 \times 10^{23} \, \text{atoms/mol} = 6.02 \times 10^{23} \, \text{atoms} \]

### Final Answer
Thus, the number of oxygen atoms present in 16 g of ozone (O₃) is \(6.02 \times 10^{23}\) atoms.

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