If ten volumes of dihydrogen gas react with five volumes of dioxygen gas, how much volume of water vapour would be produced ?

Answer

To solve the problem of how much volume of water vapor would be produced when ten volumes of dihydrogen gas react with five volumes of dioxygen gas, we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between dihydrogen (H₂) and dioxygen (O₂) to form water (H₂O) can be represented as:
\[ 2H_2 + O_2 \rightarrow 2H_2O \]

### Step 2: Balance the equation
In the balanced equation:
- 2 volumes of H₂ react with 1 volume of O₂ to produce 2 volumes of H₂O.
- This means that 2 volumes of dihydrogen will yield 2 volumes of water vapor.

### Step 3: Determine the limiting reactant
From the question, we have:
- 10 volumes of H₂
- 5 volumes of O₂

Using the stoichiometry of the balanced equation:
- For every 2 volumes of H₂, we need 1 volume of O₂.
- Therefore, 10 volumes of H₂ would require \( \frac{10}{2} = 5 \) volumes of O₂.

Since we have exactly 5 volumes of O₂ available, both reactants will completely react with each other.

### Step 4: Calculate the volume of water vapor produced
According to the balanced equation:
- 2 volumes of H₂ produce 2 volumes of H₂O.
- Therefore, 10 volumes of H₂ will produce \( 10 \) volumes of H₂O.

### Conclusion
Thus, the volume of water vapor produced is **10 volumes**.

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