An element has outer shell electronic configuration `4s^(2) 4p^(3)` . Find :-
Atomic number of next noble gas.

Which element has an outer electron configuration os s^(2)p^(4) ?

The atom having the valence shell electronic configuration 4s^(2) 4p^2 would be in

An element has atomic number 37 the electronic configuration of the element is

An element 'X' has its electronic configuration of 'K' shell is (n-5)s^(2) and it has total number of electrons in its outermost, penultimate and antipenultimate shell are 2,8 and 25 respectively then find out total number of unpaired electrons in element 'X' in their ground state.